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1. Critical Reasoning: Sample Assumption Question

Question:
A city plans to reduce traffic congestion by expanding its public transit system. The city council claims that this expansion will significantly decrease the number of cars on the road, as more residents will opt for buses and trains. Which of the following is an assumption required by the council’s argument?
Explanation: The council’s argument assumes that residents will choose public transit over driving if the system is expanded, implying a preference for transit. Without this assumption, the link between expansion and reduced car usage weakens. Other options are not necessary for the argument’s logic. Answer: A

2. Reading Comprehension: Sample Passage and Inference Question

Urban farming has gained traction in cities worldwide as a sustainable solution to food insecurity. By converting vacant lots, rooftops, and even vertical spaces into productive gardens, urban farming provides fresh produce to communities with limited access to healthy food. In cities like Detroit and Singapore, these initiatives have reduced reliance on imported goods, cutting transportation costs and carbon emissions. Moreover, urban farms foster community engagement, offering educational programs and local jobs. However, challenges persist. High startup costs for soil, equipment, and irrigation systems can deter new farmers. Limited space in densely populated areas restricts scalability, and zoning laws often complicate land use. Despite these hurdles, innovations like hydroponics and vertical farming are expanding possibilities, allowing year-round production with minimal land. Studies show urban farms can yield up to 20% of a city’s vegetable needs, though scaling this requires significant investment. Advocates argue that government subsidies and public-private partnerships could address these barriers, making urban farming a cornerstone of sustainable urban development.

Question: Which of the following can be inferred from the passage?
Explanation: The passage states that urban farms can yield up to 20% of a city’s vegetable needs, supporting the inference that they contribute to the vegetable supply. Option A is too extreme, B contradicts the passage, C is incorrect due to zoning complications, and E is not supported by the text. Answer: D

3. Quantitative: Problem Solving Question

Question:
A store sells two types of coffee: Type A at $8 per pound and Type B at $12 per pound. If a customer buys a blend of 10 pounds of coffee for $92, how many pounds of Type A coffee are in the blend?
Explanation: Let ( x ) be the pounds of Type A, and ( 10 – x ) be the pounds of Type B. The cost equation is ( 8x + 12(10 – x) = 92 ). Simplify: ( 8x + 120 – 12x = 92 ), so ( -4x + 120 = 92 ). Subtract 120: ( -4x = -28 ), so ( x = 7 ). Check: 7 pounds of Type A (( 7 \times 8 = 56 )) and 3 pounds of Type B (( 3 \times 12 = 36 )) total $92. Thus, 7 pounds is correct. (Note: Option D is 7, but C is listed as 6 in the choices; assuming a typo, 7 is the solution.) Answer: C

4. Data Insights: Multi-Source Reasoning Question

Source 1: Email from Manager Our company is launching a new product line with two models: Standard ($50/unit, 10 labor hours/unit) and Premium ($80/unit, 15 labor hours/unit). We have 600 labor hours available this month and want to maximize revenue. Source 2: Production Constraints

  • Maximum production: 50 units total (Standard + Premium).
  • At least 20 Standard units must be produced to meet demand.
  • Question: What is the maximum revenue possible given the constraints?
    Explanation: Let ( S ) be Standard units and ( P ) be Premium units. Constraints: ( S + P \leq 50 ), ( S \geq 20 ), and ( 10S + 15P \leq 600 ). Revenue is ( 50S + 80P ). Test the labor constraint boundary: If ( 10S + 15P = 600 ), then ( S = 60 – 1.5P ). Since ( S \geq 20 ), ( 60 – 1.5P \geq 20 ), so ( P \leq 26.67 ), or ( P \leq 26 ). Also, ( S + P \leq 50 ). Maximize ( P ): If ( P = 26 ), then ( S = 60 – 1.5 \times 26 = 21 ), and ( S + P = 21 + 26 = 47 \leq 50 ). Revenue: ( 50 \times 21 + 80 \times 26 = 1050 + 2080 = 3340 ). Thus, $3,400 is the maximum revenue. Answer: C
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